40511312531 has 2 divisors, whose sum is σ = 40511312532. Its totient is φ = 40511312530.

The previous prime is 40511312503. The next prime is 40511312539. The reversal of 40511312531 is 13521311504.

40511312531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-40511312531 is a prime.

It is a super-2 number, since 2×40511312531² (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 40511312531.

It is not a weakly prime, because it can be changed into another prime (40511312539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20255656265 + 20255656266.

It is an arithmetic number, because the mean of its divisors is an integer number (20255656266).

Almost surely, 2^40511312531 is an apocalyptic number.

40511312531 is a deficient number, since it is larger than the sum of its proper divisors (1).

40511312531 is an equidigital number, since it uses as much as digits as its factorization.

40511312531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 26.

The spelling of 40511312531 in words is "forty billion, five hundred eleven million, three hundred twelve thousand, five hundred thirty-one".