Search a number
-
+
40524004141 = 68635904707
BaseRepresentation
bin100101101111011010…
…110011101100101101
310212121012001201001021
4211233122303230231
51130443121113031
630341054014141
72633136231445
oct455732635455
9125535051037
1040524004141
1116205820115
127a2b4a7351
133a8a7c049a
141d66011125
1510c29e2511
hex96f6b3b2d

40524004141 has 4 divisors (see below), whose sum is σ = 40529915712. Its totient is φ = 40518092572.

The previous prime is 40524004097. The next prime is 40524004153. The reversal of 40524004141 is 14140042504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40524004141 - 27 = 40524004013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40524004181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2945491 + ... + 2959216.

It is an arithmetic number, because the mean of its divisors is an integer number (10132478928).

Almost surely, 240524004141 is an apocalyptic number.

It is an amenable number.

40524004141 is a deficient number, since it is larger than the sum of its proper divisors (5911571).

40524004141 is an equidigital number, since it uses as much as digits as its factorization.

40524004141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5911570.

The product of its (nonzero) digits is 2560, while the sum is 25.

Adding to 40524004141 its reverse (14140042504), we get a palindrome (54664046645).

The spelling of 40524004141 in words is "forty billion, five hundred twenty-four million, four thousand, one hundred forty-one".

Divisors: 1 6863 5904707 40524004141