Base | Representation |
---|---|
bin | 1011110010111101000… |
… | …00011111001010110001 |
3 | 1102202011220222100111221 |
4 | 11321132200133022301 |
5 | 23120040000003101 |
6 | 510110433305041 |
7 | 41166010260244 |
oct | 5713640371261 |
9 | 1382156870457 |
10 | 405312500401 |
11 | 14698a3815a6 |
12 | 66676405181 |
13 | 2c2b41536c3 |
14 | 1588d96d25b |
15 | a822eccaa1 |
hex | 5e5e81f2b1 |
405312500401 has 4 divisors (see below), whose sum is σ = 405330338304. Its totient is φ = 405294662500.
The previous prime is 405312500399. The next prime is 405312500419. The reversal of 405312500401 is 104005213504.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 405312500401 - 21 = 405312500399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (405312200401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8884825 + ... + 8930326.
It is an arithmetic number, because the mean of its divisors is an integer number (101332584576).
Almost surely, 2405312500401 is an apocalyptic number.
It is an amenable number.
405312500401 is a deficient number, since it is larger than the sum of its proper divisors (17837903).
405312500401 is a wasteful number, since it uses less digits than its factorization.
405312500401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17837902.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 405312500401 its reverse (104005213504), we get a palindrome (509317713905).
The spelling of 405312500401 in words is "four hundred five billion, three hundred twelve million, five hundred thousand, four hundred one".
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