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40531341301 = 113684667391
BaseRepresentation
bin100101101111110110…
…110010111111110101
310212121200212110201221
4211233312302333311
51131002010410201
630341515150341
72633255500543
oct455766627765
9125550773657
1040531341301
1116209981690
127a31a453b1
133a8c18bcb9
141d66da0d93
1510c34914a1
hex96fdb2ff5

40531341301 has 4 divisors (see below), whose sum is σ = 44216008704. Its totient is φ = 36846673900.

The previous prime is 40531341293. The next prime is 40531341349. The reversal of 40531341301 is 10314313504.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40531341301 - 23 = 40531341293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40531341371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1842333685 + ... + 1842333706.

It is an arithmetic number, because the mean of its divisors is an integer number (11054002176).

Almost surely, 240531341301 is an apocalyptic number.

It is an amenable number.

40531341301 is a deficient number, since it is larger than the sum of its proper divisors (3684667403).

40531341301 is a wasteful number, since it uses less digits than its factorization.

40531341301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3684667402.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 40531341301 its reverse (10314313504), we get a palindrome (50845654805).

The spelling of 40531341301 in words is "forty billion, five hundred thirty-one million, three hundred forty-one thousand, three hundred one".

Divisors: 1 11 3684667391 40531341301