Base | Representation |
---|---|
bin | 100101101111111001… |
… | …101111000001001001 |
3 | 10212121202022121011100 |
4 | 211233321233001021 |
5 | 1131002210031213 |
6 | 30341543452013 |
7 | 2633265156042 |
oct | 455771570111 |
9 | 125552277140 |
10 | 40532111433 |
11 | 1620a358260 |
12 | 7a32157009 |
13 | 3a8c39b6b8 |
14 | 1d671218c9 |
15 | 10c3594773 |
hex | 96fe6f049 |
40532111433 has 24 divisors (see below), whose sum is σ = 67625771616. Its totient is φ = 23119920000.
The previous prime is 40532111413. The next prime is 40532111441. The reversal of 40532111433 is 33411123504.
It is a happy number.
40532111433 is a `hidden beast` number, since 405 + 3 + 211 + 1 + 43 + 3 = 666.
It is not a de Polignac number, because 40532111433 - 212 = 40532107337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40532111397 and 40532111406.
It is not an unprimeable number, because it can be changed into a prime (40532111413) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12039943 + ... + 12043308.
It is an arithmetic number, because the mean of its divisors is an integer number (2817740484).
Almost surely, 240532111433 is an apocalyptic number.
It is an amenable number.
40532111433 is a deficient number, since it is larger than the sum of its proper divisors (27093660183).
40532111433 is a wasteful number, since it uses less digits than its factorization.
40532111433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24083285 (or 24083282 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 40532111433 its reverse (33411123504), we get a palindrome (73943234937).
The spelling of 40532111433 in words is "forty billion, five hundred thirty-two million, one hundred eleven thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.165 sec. • engine limits •