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405341115353 is a prime number
BaseRepresentation
bin1011110011000000011…
…01101001001111011001
31102202020220211010211222
411321200031221033121
523120114311142403
6510113334501425
741166505426616
oct5714015511731
91382226733758
10405341115353
111469a4546419
1266683b04875
132c2ba062125
141589369b50d
15a825781338
hex5e603693d9

405341115353 has 2 divisors, whose sum is σ = 405341115354. Its totient is φ = 405341115352.

The previous prime is 405341115343. The next prime is 405341115371. The reversal of 405341115353 is 353511143504.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 242587771024 + 162753344329 = 492532^2 + 403427^2 .

It is a cyclic number.

It is not a de Polignac number, because 405341115353 - 218 = 405340853209 is a prime.

It is a super-2 number, since 2×4053411153532 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (405341115313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202670557676 + 202670557677.

It is an arithmetic number, because the mean of its divisors is an integer number (202670557677).

Almost surely, 2405341115353 is an apocalyptic number.

It is an amenable number.

405341115353 is a deficient number, since it is larger than the sum of its proper divisors (1).

405341115353 is an equidigital number, since it uses as much as digits as its factorization.

405341115353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 405341115353 its reverse (353511143504), we get a palindrome (758852258857).

The spelling of 405341115353 in words is "four hundred five billion, three hundred forty-one million, one hundred fifteen thousand, three hundred fifty-three".