Base | Representation |
---|---|
bin | 1011110011000000011… |
… | …01101001001111011001 |
3 | 1102202020220211010211222 |
4 | 11321200031221033121 |
5 | 23120114311142403 |
6 | 510113334501425 |
7 | 41166505426616 |
oct | 5714015511731 |
9 | 1382226733758 |
10 | 405341115353 |
11 | 1469a4546419 |
12 | 66683b04875 |
13 | 2c2ba062125 |
14 | 1589369b50d |
15 | a825781338 |
hex | 5e603693d9 |
405341115353 has 2 divisors, whose sum is σ = 405341115354. Its totient is φ = 405341115352.
The previous prime is 405341115343. The next prime is 405341115371. The reversal of 405341115353 is 353511143504.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 242587771024 + 162753344329 = 492532^2 + 403427^2 .
It is a cyclic number.
It is not a de Polignac number, because 405341115353 - 218 = 405340853209 is a prime.
It is a super-2 number, since 2×4053411153532 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (405341115313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202670557676 + 202670557677.
It is an arithmetic number, because the mean of its divisors is an integer number (202670557677).
Almost surely, 2405341115353 is an apocalyptic number.
It is an amenable number.
405341115353 is a deficient number, since it is larger than the sum of its proper divisors (1).
405341115353 is an equidigital number, since it uses as much as digits as its factorization.
405341115353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 405341115353 its reverse (353511143504), we get a palindrome (758852258857).
The spelling of 405341115353 in words is "four hundred five billion, three hundred forty-one million, one hundred fifteen thousand, three hundred fifty-three".
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