Base | Representation |
---|---|
bin | 100101110001000010… |
… | …001110000110011011 |
3 | 10212200002001222120100 |
4 | 211301002032012123 |
5 | 1131022041104430 |
6 | 30343503030443 |
7 | 2633615526402 |
oct | 456102160633 |
9 | 125602058510 |
10 | 40551113115 |
11 | 1621a056527 |
12 | 7a3859b423 |
13 | 3a932c25b6 |
14 | 1d6986a639 |
15 | 10c5099960 |
hex | 97108e19b |
40551113115 has 24 divisors (see below), whose sum is σ = 74423220768. Its totient is φ = 20355068160.
The previous prime is 40551113107. The next prime is 40551113117. The reversal of 40551113115 is 51131115504.
40551113115 is a `hidden beast` number, since 4 + 0 + 5 + 511 + 131 + 15 = 666.
It is not a de Polignac number, because 40551113115 - 23 = 40551113107 is a prime.
It is not an unprimeable number, because it can be changed into a prime (40551113117) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 26503231 + ... + 26504760.
It is an arithmetic number, because the mean of its divisors is an integer number (3100967532).
Almost surely, 240551113115 is an apocalyptic number.
40551113115 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
40551113115 is a deficient number, since it is larger than the sum of its proper divisors (33872107653).
40551113115 is a wasteful number, since it uses less digits than its factorization.
40551113115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 53008019 (or 53008016 counting only the distinct ones).
The product of its (nonzero) digits is 1500, while the sum is 27.
Adding to 40551113115 its reverse (51131115504), we get a palindrome (91682228619).
The spelling of 40551113115 in words is "forty billion, five hundred fifty-one million, one hundred thirteen thousand, one hundred fifteen".
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