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4055225503 = 71165749697
BaseRepresentation
bin1111000110110101…
…1101010010011111
3101110121121210121011
43301231131102133
531301114204003
61510221320051
7202330563610
oct36155352237
911417553534
104055225503
1117a1083a3a
12952106027
134c81b9424
142a680bc07
1518b03346d
hexf1b5d49f

4055225503 has 8 divisors (see below), whose sum is σ = 4635034272. Its totient is φ = 3475539456.

The previous prime is 4055225501. The next prime is 4055225513. The reversal of 4055225503 is 3055225504.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4055225503 - 21 = 4055225501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4055225501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56751 + ... + 106447.

It is an arithmetic number, because the mean of its divisors is an integer number (579379284).

Almost surely, 24055225503 is an apocalyptic number.

4055225503 is a deficient number, since it is larger than the sum of its proper divisors (579808769).

4055225503 is a wasteful number, since it uses less digits than its factorization.

4055225503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61361.

The product of its (nonzero) digits is 30000, while the sum is 31.

The square root of 4055225503 is about 63680.6525013681. The cubic root of 4055225503 is about 1594.6731055067.

Subtracting from 4055225503 its reverse (3055225504), we obtain a palindrome (999999999).

The spelling of 4055225503 in words is "four billion, fifty-five million, two hundred twenty-five thousand, five hundred three".

Divisors: 1 7 11657 49697 81599 347879 579317929 4055225503