Base | Representation |
---|---|
bin | 10010011100010001011011… |
… | …11001100000001100101011 |
3 | 12022120220120121210001110211 |
4 | 21032020231321200030223 |
5 | 20303413241410221033 |
6 | 222130103154521551 |
7 | 11353630145051263 |
oct | 1116105571401453 |
9 | 168526517701424 |
10 | 40553851257643 |
11 | 11a15878886479 |
12 | 466b7368962b7 |
13 | 198229a328319 |
14 | a02b617047a3 |
15 | 4a4d733882cd |
hex | 24e22de6032b |
40553851257643 has 2 divisors, whose sum is σ = 40553851257644. Its totient is φ = 40553851257642.
The previous prime is 40553851257613. The next prime is 40553851257649. The reversal of 40553851257643 is 34675215835504.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40553851257643 - 25 = 40553851257611 is a prime.
It is a super-2 number, since 2×405538512576432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40553851257649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20276925628821 + 20276925628822.
It is an arithmetic number, because the mean of its divisors is an integer number (20276925628822).
Almost surely, 240553851257643 is an apocalyptic number.
40553851257643 is a deficient number, since it is larger than the sum of its proper divisors (1).
40553851257643 is an equidigital number, since it uses as much as digits as its factorization.
40553851257643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480000, while the sum is 58.
The spelling of 40553851257643 in words is "forty trillion, five hundred fifty-three billion, eight hundred fifty-one million, two hundred fifty-seven thousand, six hundred forty-three".
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