406113131 has 2 divisors, whose sum is σ = 406113132. Its totient is φ = 406113130.

The previous prime is 406113121. The next prime is 406113157. The reversal of 406113131 is 131311604.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-406113131 is a prime.

It is a super-2 number, since 2×406113131² = 329855750341246322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (406113121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 203056565 + 203056566.

It is an arithmetic number, because the mean of its divisors is an integer number (203056566).

Almost surely, 2^406113131 is an apocalyptic number.

406113131 is a deficient number, since it is larger than the sum of its proper divisors (1).

406113131 is an equidigital number, since it uses as much as digits as its factorization.

406113131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

The square root of 406113131 is about 20152.2487827041. The cubic root of 406113131 is about 740.5408336313.

Adding to 406113131 its reverse (131311604), we get a palindrome (537424735).

The spelling of 406113131 in words is "four hundred six million, one hundred thirteen thousand, one hundred thirty-one".