Base | Representation |
---|---|
bin | 111011000110100011110… |
… | …111011011110000100100 |
3 | 112101021102110012122101112 |
4 | 323012203313123300210 |
5 | 1013020414242000143 |
6 | 12345454013044152 |
7 | 566301406353530 |
oct | 73064367336044 |
9 | 15337373178345 |
10 | 4061493312548 |
11 | 1326519101531 |
12 | 557189a86658 |
13 | 235cc6a45cc9 |
14 | 100812274bc0 |
15 | 709ae885e18 |
hex | 3b1a3ddbc24 |
4061493312548 has 48 divisors (see below), whose sum is σ = 8402524569600. Its totient is φ = 1680973460640.
The previous prime is 4061493312523. The next prime is 4061493312551. The reversal of 4061493312548 is 8452133941604.
It is a super-3 number, since 3×40614933125483 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4061493312496 and 4061493312505.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4468508 + ... + 5300051.
It is an arithmetic number, because the mean of its divisors is an integer number (175052595200).
Almost surely, 24061493312548 is an apocalyptic number.
It is an amenable number.
4061493312548 is an abundant number, since it is smaller than the sum of its proper divisors (4341031257052).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4061493312548 is a wasteful number, since it uses less digits than its factorization.
4061493312548 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9769080 (or 9769078 counting only the distinct ones).
The product of its (nonzero) digits is 2488320, while the sum is 50.
The spelling of 4061493312548 in words is "four trillion, sixty-one billion, four hundred ninety-three million, three hundred twelve thousand, five hundred forty-eight".
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