4061493312551 has 2 divisors, whose sum is σ = 4061493312552. Its totient is φ = 4061493312550.

The previous prime is 4061493312523. The next prime is 4061493312553. The reversal of 4061493312551 is 1552133941604.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4061493312551 - 2¹⁰ = 4061493311527 is a prime.

Together with 4061493312553, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4061493312553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2030746656275 + 2030746656276.

It is an arithmetic number, because the mean of its divisors is an integer number (2030746656276).

Almost surely, 2^{4061493312551} is an apocalyptic number.

4061493312551 is a deficient number, since it is larger than the sum of its proper divisors (1).

4061493312551 is an equidigital number, since it uses as much as digits as its factorization.

4061493312551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 44.

The spelling of 4061493312551 in words is "four trillion, sixty-one billion, four hundred ninety-three million, three hundred twelve thousand, five hundred fifty-one".