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4061593411991 = 4199063253951
BaseRepresentation
bin111011000110101001110…
…101010010000110010111
3112101021200102120020000022
4323012221311102012113
51013021120403140431
612345511550335355
7566304033241613
oct73065165220627
915337612506008
104061593411991
11132656a660745
125571b74ba55b
132360116c2b4b
14100821690343
15709b855a07b
hex3b1a9d52197

4061593411991 has 4 divisors (see below), whose sum is σ = 4160656665984. Its totient is φ = 3962530158000.

The previous prime is 4061593411987. The next prime is 4061593412021. The reversal of 4061593411991 is 1991143951604.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4061593411991 - 22 = 4061593411987 is a prime.

It is a super-3 number, since 3×40615934119913 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4061593411921) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49531626935 + ... + 49531627016.

It is an arithmetic number, because the mean of its divisors is an integer number (1040164166496).

Almost surely, 24061593411991 is an apocalyptic number.

4061593411991 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

4061593411991 is a deficient number, since it is larger than the sum of its proper divisors (99063253993).

4061593411991 is an equidigital number, since it uses as much as digits as its factorization.

4061593411991 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99063253992.

The product of its (nonzero) digits is 1049760, while the sum is 53.

The spelling of 4061593411991 in words is "four trillion, sixty-one billion, five hundred ninety-three million, four hundred eleven thousand, nine hundred ninety-one".

Divisors: 1 41 99063253951 4061593411991