Base | Representation |
---|---|
bin | 111011001001100101110… |
… | …000100000101010001001 |
3 | 112101120211011020101102102 |
4 | 323021211300200222021 |
5 | 1013044100021340023 |
6 | 12351152455243145 |
7 | 566445126200435 |
oct | 73114560405211 |
9 | 15346734211372 |
10 | 4064746277513 |
11 | 1327938340229 |
12 | 5579373794b5 |
13 | 2363c496a64c |
14 | 100a402c99c5 |
15 | 70b00247628 |
hex | 3b265c20a89 |
4064746277513 has 2 divisors, whose sum is σ = 4064746277514. Its totient is φ = 4064746277512.
The previous prime is 4064746277479. The next prime is 4064746277531. The reversal of 4064746277513 is 3157726474604.
Together with next prime (4064746277531) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4056872732224 + 7873545289 = 2014168^2 + 88733^2 .
It is a cyclic number.
It is not a de Polignac number, because 4064746277513 - 210 = 4064746276489 is a prime.
It is not a weakly prime, because it can be changed into another prime (4064746277113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2032373138756 + 2032373138757.
It is an arithmetic number, because the mean of its divisors is an integer number (2032373138757).
Almost surely, 24064746277513 is an apocalyptic number.
It is an amenable number.
4064746277513 is a deficient number, since it is larger than the sum of its proper divisors (1).
4064746277513 is an equidigital number, since it uses as much as digits as its factorization.
4064746277513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23708160, while the sum is 56.
The spelling of 4064746277513 in words is "four trillion, sixty-four billion, seven hundred forty-six million, two hundred seventy-seven thousand, five hundred thirteen".
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