Base | Representation |
---|---|
bin | 10010011111001100110010… |
… | …11101101011011111011001 |
3 | 12022221112012211112021112122 |
4 | 21033212121131223133121 |
5 | 20312040243134313001 |
6 | 222244220355551025 |
7 | 11364120632410115 |
oct | 1117463135533731 |
9 | 168845184467478 |
10 | 40654440151001 |
11 | 11a544a66738a6 |
12 | 46871298bb475 |
13 | 198b90ab45171 |
14 | a07984a5a745 |
15 | 4a77ae149b1b |
hex | 24f99976b7d9 |
40654440151001 has 2 divisors, whose sum is σ = 40654440151002. Its totient is φ = 40654440151000.
The previous prime is 40654440150949. The next prime is 40654440151043. The reversal of 40654440151001 is 10015104445604.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21926967525376 + 18727472625625 = 4682624^2 + 4327525^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40654440151001 is a prime.
It is not a weakly prime, because it can be changed into another prime (40654440151901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20327220075500 + 20327220075501.
It is an arithmetic number, because the mean of its divisors is an integer number (20327220075501).
Almost surely, 240654440151001 is an apocalyptic number.
It is an amenable number.
40654440151001 is a deficient number, since it is larger than the sum of its proper divisors (1).
40654440151001 is an equidigital number, since it uses as much as digits as its factorization.
40654440151001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 40654440151001 its reverse (10015104445604), we get a palindrome (50669544596605).
The spelling of 40654440151001 in words is "forty trillion, six hundred fifty-four billion, four hundred forty million, one hundred fifty-one thousand, one".
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