Base | Representation |
---|---|
bin | 100101110111001111… |
… | …111011011101100011 |
3 | 10212221100020210020112 |
4 | 211313033323131203 |
5 | 1131230233320313 |
6 | 30402105401535 |
7 | 2636322641516 |
oct | 456717733543 |
9 | 125840223215 |
10 | 40655370083 |
11 | 16272995309 |
12 | 7a674992ab |
13 | 3aaba96903 |
14 | 1d79648d7d |
15 | 10ce2e08a8 |
hex | 9773fb763 |
40655370083 has 2 divisors, whose sum is σ = 40655370084. Its totient is φ = 40655370082.
The previous prime is 40655370029. The next prime is 40655370109. The reversal of 40655370083 is 38007355604.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40655370083 - 28 = 40655369827 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40655370083.
It is not a weakly prime, because it can be changed into another prime (40655370013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20327685041 + 20327685042.
It is an arithmetic number, because the mean of its divisors is an integer number (20327685042).
Almost surely, 240655370083 is an apocalyptic number.
40655370083 is a deficient number, since it is larger than the sum of its proper divisors (1).
40655370083 is an equidigital number, since it uses as much as digits as its factorization.
40655370083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 40655370083 in words is "forty billion, six hundred fifty-five million, three hundred seventy thousand, eighty-three".
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