Base | Representation |
---|---|
bin | 10010011111011111011010… |
… | …00011100000110010011001 |
3 | 12022222111000012220211010201 |
4 | 21033233231003200302121 |
5 | 20312221224210342103 |
6 | 222252552110542201 |
7 | 11364623355155302 |
oct | 1117575503406231 |
9 | 168874005824121 |
10 | 40664432512153 |
11 | 11a5876404070a |
12 | 4689058207961 |
13 | 198c8410896b8 |
14 | a08251b917a9 |
15 | 4a7b964e951d |
hex | 24fbed0e0c99 |
40664432512153 has 2 divisors, whose sum is σ = 40664432512154. Its totient is φ = 40664432512152.
The previous prime is 40664432512111. The next prime is 40664432512213. The reversal of 40664432512153 is 35121523446604.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39115980792729 + 1548451719424 = 6254277^2 + 1244368^2 .
It is a cyclic number.
It is not a de Polignac number, because 40664432512153 - 221 = 40664430415001 is a prime.
It is not a weakly prime, because it can be changed into another prime (40664432512103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20332216256076 + 20332216256077.
It is an arithmetic number, because the mean of its divisors is an integer number (20332216256077).
Almost surely, 240664432512153 is an apocalyptic number.
It is an amenable number.
40664432512153 is a deficient number, since it is larger than the sum of its proper divisors (1).
40664432512153 is an equidigital number, since it uses as much as digits as its factorization.
40664432512153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2073600, while the sum is 46.
Adding to 40664432512153 its reverse (35121523446604), we get a palindrome (75785955958757).
The spelling of 40664432512153 in words is "forty trillion, six hundred sixty-four billion, four hundred thirty-two million, five hundred twelve thousand, one hundred fifty-three".
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