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4069000531253 = 78811187555857
BaseRepresentation
bin111011001101100011010…
…101001100110100110101
3112101222210122100212102202
4323031203111030310311
51013131303114000003
612353134550514245
7566655424563530
oct73154325146465
915358718325382
104069000531253
1113297207a3009
12558724065985
13236922160958
14100d25305a17
1570c9d992088
hex3b36354cd35

4069000531253 has 16 divisors (see below), whose sum is σ = 4659495249024. Its totient is φ = 3480814740480.

The previous prime is 4069000531199. The next prime is 4069000531279. The reversal of 4069000531253 is 3521350009604.

It is a de Polignac number, because none of the positive numbers 2k-4069000531253 is a prime.

It is a super-3 number, since 3×40690005312533 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4069000534253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7042301 + ... + 7598157.

It is an arithmetic number, because the mean of its divisors is an integer number (291218453064).

Almost surely, 24069000531253 is an apocalyptic number.

It is an amenable number.

4069000531253 is a deficient number, since it is larger than the sum of its proper divisors (590494717771).

4069000531253 is a wasteful number, since it uses less digits than its factorization.

4069000531253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 557932.

The product of its (nonzero) digits is 97200, while the sum is 38.

The spelling of 4069000531253 in words is "four trillion, sixty-nine billion, five hundred thirty-one thousand, two hundred fifty-three".

Divisors: 1 7 881 1187 6167 8309 555857 1045747 3890999 7320229 489710017 659802259 3427970119 4618615813 581285790179 4069000531253