Base | Representation |
---|---|
bin | 10010100001011111100101… |
… | …11101011001100011110001 |
3 | 12100020001122022010202020011 |
4 | 21100233302331121203301 |
5 | 20314333144232042323 |
6 | 222344332555014521 |
7 | 11402610635115115 |
oct | 1120576275314361 |
9 | 170201568122204 |
10 | 40733251049713 |
11 | 11a84969338542 |
12 | 469a46343a441 |
13 | 199618a800441 |
14 | a0b6dd901745 |
15 | 4a987303220d |
hex | 250bf2f598f1 |
40733251049713 has 2 divisors, whose sum is σ = 40733251049714. Its totient is φ = 40733251049712.
The previous prime is 40733251049663. The next prime is 40733251049717. The reversal of 40733251049713 is 31794015233704.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40308124881424 + 425126168289 = 6348868^2 + 652017^2 .
It is a cyclic number.
It is not a de Polignac number, because 40733251049713 - 213 = 40733251041521 is a prime.
It is not a weakly prime, because it can be changed into another prime (40733251049717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20366625524856 + 20366625524857.
It is an arithmetic number, because the mean of its divisors is an integer number (20366625524857).
Almost surely, 240733251049713 is an apocalyptic number.
It is an amenable number.
40733251049713 is a deficient number, since it is larger than the sum of its proper divisors (1).
40733251049713 is an equidigital number, since it uses as much as digits as its factorization.
40733251049713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1905120, while the sum is 49.
The spelling of 40733251049713 in words is "forty trillion, seven hundred thirty-three billion, two hundred fifty-one million, forty-nine thousand, seven hundred thirteen".
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