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4091638140553 is a prime number
BaseRepresentation
bin111011100010101000101…
…000110100111010001001
3112111011020022000120102211
4323202220220310322021
51014014133330444203
612411401141225121
7601416415231465
oct73425050647211
915434208016384
104091638140553
111338288074a27
12560ba14021a1
13238abc118b42
14102071a1d4a5
157167606bc6d
hex3b8a8a34e89

4091638140553 has 2 divisors, whose sum is σ = 4091638140554. Its totient is φ = 4091638140552.

The previous prime is 4091638140479. The next prime is 4091638140571. The reversal of 4091638140553 is 3550418361904.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2656127436169 + 1435510704384 = 1629763^2 + 1198128^2 .

It is a cyclic number.

It is not a de Polignac number, because 4091638140553 - 221 = 4091636043401 is a prime.

It is a super-2 number, since 2×40916381405532 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4091638140497 and 4091638140506.

It is not a weakly prime, because it can be changed into another prime (4091638140053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2045819070276 + 2045819070277.

It is an arithmetic number, because the mean of its divisors is an integer number (2045819070277).

Almost surely, 24091638140553 is an apocalyptic number.

It is an amenable number.

4091638140553 is a deficient number, since it is larger than the sum of its proper divisors (1).

4091638140553 is an equidigital number, since it uses as much as digits as its factorization.

4091638140553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 49.

The spelling of 4091638140553 in words is "four trillion, ninety-one billion, six hundred thirty-eight million, one hundred forty thousand, five hundred fifty-three".