Base | Representation |
---|---|
bin | 111011100111111011100… |
… | …010011110100000010011 |
3 | 112111200220112212201122102 |
4 | 323213323202132200103 |
5 | 1014112304412432042 |
6 | 12414141252031015 |
7 | 602010335644616 |
oct | 73477342364023 |
9 | 15450815781572 |
10 | 4097323952147 |
11 | 133a735610378 |
12 | 56210960246b |
13 | 2394b70899ba |
14 | 102450c0417d |
15 | 718aa2e1b32 |
hex | 3b9fb89e813 |
4097323952147 has 2 divisors, whose sum is σ = 4097323952148. Its totient is φ = 4097323952146.
The previous prime is 4097323952123. The next prime is 4097323952173. The reversal of 4097323952147 is 7412593237904.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4097323952147 - 212 = 4097323948051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4097323952092 and 4097323952101.
It is not a weakly prime, because it can be changed into another prime (4097323957147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2048661976073 + 2048661976074.
It is an arithmetic number, because the mean of its divisors is an integer number (2048661976074).
Almost surely, 24097323952147 is an apocalyptic number.
4097323952147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4097323952147 is an equidigital number, since it uses as much as digits as its factorization.
4097323952147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11430720, while the sum is 56.
The spelling of 4097323952147 in words is "four trillion, ninety-seven billion, three hundred twenty-three million, nine hundred fifty-two thousand, one hundred forty-seven".
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