Base | Representation |
---|---|
bin | 100110001010001100… |
… | …110010001001101001 |
3 | 10220202111111221101221 |
4 | 212022030302021221 |
5 | 1132403132000432 |
6 | 30453424142041 |
7 | 2650233260626 |
oct | 461214621151 |
9 | 126674457357 |
10 | 40973312617 |
11 | 16416404236 |
12 | 7b35a67921 |
13 | 3b2c9074a3 |
14 | 1da996d34d |
15 | 10ec195b97 |
hex | 98a332269 |
40973312617 has 2 divisors, whose sum is σ = 40973312618. Its totient is φ = 40973312616.
The previous prime is 40973312537. The next prime is 40973312647. The reversal of 40973312617 is 71621337904.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29365620496 + 11607692121 = 171364^2 + 107739^2 .
It is a cyclic number.
It is not a de Polignac number, because 40973312617 - 223 = 40964924009 is a prime.
It is a super-3 number, since 3×409733126173 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (40973312647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20486656308 + 20486656309.
It is an arithmetic number, because the mean of its divisors is an integer number (20486656309).
Almost surely, 240973312617 is an apocalyptic number.
It is an amenable number.
40973312617 is a deficient number, since it is larger than the sum of its proper divisors (1).
40973312617 is an equidigital number, since it uses as much as digits as its factorization.
40973312617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 190512, while the sum is 43.
The spelling of 40973312617 in words is "forty billion, nine hundred seventy-three million, three hundred twelve thousand, six hundred seventeen".
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