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409991725441 is a prime number
BaseRepresentation
bin1011111011101010110…
…10010100000110000001
31110012021000202121120001
411331311122110012001
523204130340203231
6512203025320001
741422656110614
oct5756532240601
91405230677501
10409991725441
11148970705631
1267561496001
132c87b6bc40c
1415bb51b017b
15a9e8bbeb61
hex5f75694181

409991725441 has 2 divisors, whose sum is σ = 409991725442. Its totient is φ = 409991725440.

The previous prime is 409991725433. The next prime is 409991725453. The reversal of 409991725441 is 144527199904.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 243735740416 + 166255985025 = 493696^2 + 407745^2 .

It is a cyclic number.

It is not a de Polignac number, because 409991725441 - 23 = 409991725433 is a prime.

It is not a weakly prime, because it can be changed into another prime (409991725471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 204995862720 + 204995862721.

It is an arithmetic number, because the mean of its divisors is an integer number (204995862721).

Almost surely, 2409991725441 is an apocalyptic number.

It is an amenable number.

409991725441 is a deficient number, since it is larger than the sum of its proper divisors (1).

409991725441 is an equidigital number, since it uses as much as digits as its factorization.

409991725441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 409991725441 in words is "four hundred nine billion, nine hundred ninety-one million, seven hundred twenty-five thousand, four hundred forty-one".