4100113301 has 4 divisors (see below), whose sum is σ = 4210927212. Its totient is φ = 3989299392.

The previous prime is 4100113279. The next prime is 4100113309. The reversal of 4100113301 is 1033110014.

4100113301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1033110014 = 2 ⋅516555007.

It can be written as a sum of positive squares in 2 ways, for example, as 2362057201 + 1738056100 = 48601^2 + 41690^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4100113301 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4100113309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55406900 + ... + 55406973.

It is an arithmetic number, because the mean of its divisors is an integer number (1052731803).

Almost surely, 2^4100113301 is an apocalyptic number.

It is an amenable number.

4100113301 is a deficient number, since it is larger than the sum of its proper divisors (110813911).

4100113301 is a wasteful number, since it uses less digits than its factorization.

4100113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110813910.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 4100113301 is about 64032.1271003861. The cubic root of 4100113301 is about 1600.5354068849.

Adding to 4100113301 its reverse (1033110014), we get a palindrome (5133223315).

The spelling of 4100113301 in words is "four billion, one hundred million, one hundred thirteen thousand, three hundred one".