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410012113 = 797603847
BaseRepresentation
bin11000011100000…
…100100111010001
31001120111202212211
4120130010213101
51314430341423
6104403552121
713106021410
oct3034044721
91046452784
10410012113
111a0494195
12b538b641
1366c38824
143c64d477
1525ee010d
hex187049d1

410012113 has 8 divisors (see below), whose sum is σ = 473416832. Its totient is φ = 347815296.

The previous prime is 410012101. The next prime is 410012117. The reversal of 410012113 is 311210014.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-410012113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 410012093 and 410012102.

It is not an unprimeable number, because it can be changed into a prime (410012117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 301245 + ... + 302602.

It is an arithmetic number, because the mean of its divisors is an integer number (59177104).

Almost surely, 2410012113 is an apocalyptic number.

It is an amenable number.

410012113 is a deficient number, since it is larger than the sum of its proper divisors (63404719).

410012113 is an equidigital number, since it uses as much as digits as its factorization.

410012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 603951.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 410012113 is about 20248.7558383225. The cubic root of 410012113 is about 742.9032000871.

Adding to 410012113 its reverse (311210014), we get a palindrome (721222127).

The spelling of 410012113 in words is "four hundred ten million, twelve thousand, one hundred thirteen".

Divisors: 1 7 97 679 603847 4226929 58573159 410012113