410021431200131 has 2 divisors, whose sum is σ = 410021431200132. Its totient is φ = 410021431200130.

The previous prime is 410021431200091. The next prime is 410021431200149. The reversal of 410021431200131 is 131002134120014.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-410021431200131 is a prime.

It is a super-2 number, since 2×410021431200131² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 410021431200097 and 410021431200106.

It is not a weakly prime, because it can be changed into another prime (410021431200151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205010715600065 + 205010715600066.

It is an arithmetic number, because the mean of its divisors is an integer number (205010715600066).

Almost surely, 2^{410021431200131} is an apocalyptic number.

410021431200131 is a deficient number, since it is larger than the sum of its proper divisors (1).

410021431200131 is an equidigital number, since it uses as much as digits as its factorization.

410021431200131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 410021431200131 its reverse (131002134120014), we get a palindrome (541023565320145).

The spelling of 410021431200131 in words is "four hundred ten trillion, twenty-one billion, four hundred thirty-one million, two hundred thousand, one hundred thirty-one".