Base | Representation |
---|---|
bin | 10010101001011000001000… |
… | …00100110000010000110010 |
3 | 12101011221210200222112102020 |
4 | 21110230010010300100302 |
5 | 20333302420002130114 |
6 | 223113011100532310 |
7 | 11431310226605106 |
oct | 1124540404602062 |
9 | 171157720875366 |
10 | 41004121130034 |
11 | 12079828447a57 |
12 | 4722a59251096 |
13 | 19b58975b608a |
14 | a1a877da7906 |
15 | 4b1928183aa9 |
hex | 254b04130432 |
41004121130034 has 8 divisors (see below), whose sum is σ = 82008242260080. Its totient is φ = 13668040376676.
The previous prime is 41004121129997. The next prime is 41004121130087. The reversal of 41004121130034 is 43003112140014.
It is a sphenic number, since it is the product of 3 distinct primes.
41004121130034 is an admirable number.
It is a junction number, because it is equal to n+sod(n) for n = 41004121129986 and 41004121130013.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3417010094164 + ... + 3417010094175.
It is an arithmetic number, because the mean of its divisors is an integer number (10251030282510).
Almost surely, 241004121130034 is an apocalyptic number.
41004121130034 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41004121130034 is a wasteful number, since it uses less digits than its factorization.
41004121130034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6834020188344.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 41004121130034 its reverse (43003112140014), we get a palindrome (84007233270048).
The spelling of 41004121130034 in words is "forty-one trillion, four billion, one hundred twenty-one million, one hundred thirty thousand, thirty-four".
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