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41004121130034 = 236834020188339
BaseRepresentation
bin10010101001011000001000…
…00100110000010000110010
312101011221210200222112102020
421110230010010300100302
520333302420002130114
6223113011100532310
711431310226605106
oct1124540404602062
9171157720875366
1041004121130034
1112079828447a57
124722a59251096
1319b58975b608a
14a1a877da7906
154b1928183aa9
hex254b04130432

41004121130034 has 8 divisors (see below), whose sum is σ = 82008242260080. Its totient is φ = 13668040376676.

The previous prime is 41004121129997. The next prime is 41004121130087. The reversal of 41004121130034 is 43003112140014.

It is a sphenic number, since it is the product of 3 distinct primes.

41004121130034 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 41004121129986 and 41004121130013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3417010094164 + ... + 3417010094175.

It is an arithmetic number, because the mean of its divisors is an integer number (10251030282510).

Almost surely, 241004121130034 is an apocalyptic number.

41004121130034 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41004121130034 is a wasteful number, since it uses less digits than its factorization.

41004121130034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6834020188344.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 41004121130034 its reverse (43003112140014), we get a palindrome (84007233270048).

The spelling of 41004121130034 in words is "forty-one trillion, four billion, one hundred twenty-one million, one hundred thirty thousand, thirty-four".

Divisors: 1 2 3 6 6834020188339 13668040376678 20502060565017 41004121130034