Base | Representation |
---|---|
bin | 111011101010110100101… |
… | …011001001001101001001 |
3 | 112111222221000110202212002 |
4 | 323222310223021031021 |
5 | 1014140140040243121 |
6 | 12415413405400345 |
7 | 602150323000463 |
oct | 73526453111511 |
9 | 15458830422762 |
10 | 4100430009161 |
11 | 1340a89929a42 |
12 | 5628358690b5 |
13 | 239890725965 |
14 | 102667537133 |
15 | 719dcd34e0b |
hex | 3bab4ac9349 |
4100430009161 has 2 divisors, whose sum is σ = 4100430009162. Its totient is φ = 4100430009160.
The previous prime is 4100430009139. The next prime is 4100430009239. The reversal of 4100430009161 is 1619000340014.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2834444983561 + 1265985025600 = 1683581^2 + 1125160^2 .
It is a cyclic number.
It is not a de Polignac number, because 4100430009161 - 218 = 4100429747017 is a prime.
It is not a weakly prime, because it can be changed into another prime (4100430009121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2050215004580 + 2050215004581.
It is an arithmetic number, because the mean of its divisors is an integer number (2050215004581).
Almost surely, 24100430009161 is an apocalyptic number.
It is an amenable number.
4100430009161 is a deficient number, since it is larger than the sum of its proper divisors (1).
4100430009161 is an equidigital number, since it uses as much as digits as its factorization.
4100430009161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 4100430009161 its reverse (1619000340014), we get a palindrome (5719430349175).
The spelling of 4100430009161 in words is "four trillion, one hundred billion, four hundred thirty million, nine thousand, one hundred sixty-one".
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