Base | Representation |
---|---|
bin | 111011101101010011111… |
… | …100110111001011001001 |
3 | 112112020211020201201102020 |
4 | 323231103330313023021 |
5 | 1014211123132344431 |
6 | 12420534504355053 |
7 | 602303461341426 |
oct | 73552374671311 |
9 | 15466736651366 |
10 | 4103102231241 |
11 | 1342130272a42 |
12 | 563260775a89 |
13 | 239bc8234960 |
14 | 10283c3b8d4d |
15 | 71ae772e696 |
hex | 3bb53f372c9 |
4103102231241 has 32 divisors (see below), whose sum is σ = 5977629600768. Its totient is φ = 2488166614080.
The previous prime is 4103102231201. The next prime is 4103102231287. The reversal of 4103102231241 is 1421322013014.
4103102231241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4103102231241 - 26 = 4103102231177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4103102231201) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5129130 + ... + 5874876.
It is an arithmetic number, because the mean of its divisors is an integer number (186800925024).
Almost surely, 24103102231241 is an apocalyptic number.
It is an amenable number.
4103102231241 is a deficient number, since it is larger than the sum of its proper divisors (1874527369527).
4103102231241 is a wasteful number, since it uses less digits than its factorization.
4103102231241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 747821.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 4103102231241 its reverse (1421322013014), we get a palindrome (5524424244255).
It can be divided in two parts, 410310 and 2231241, that added together give a triangular number (2641551 = T2298).
The spelling of 4103102231241 in words is "four trillion, one hundred three billion, one hundred two million, two hundred thirty-one thousand, two hundred forty-one".
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