Base | Representation |
---|---|
bin | 11000011111110… |
… | …111000001110001 |
3 | 1001122101012220221 |
4 | 120133313001301 |
5 | 1320204130131 |
6 | 104441133041 |
7 | 13120325266 |
oct | 3037670161 |
9 | 1048335827 |
10 | 411005041 |
11 | 1a1002197 |
12 | b578a181 |
13 | 671c5765 |
14 | 3c82b26d |
15 | 26139411 |
hex | 187f7071 |
411005041 has 2 divisors, whose sum is σ = 411005042. Its totient is φ = 411005040.
The previous prime is 411005029. The next prime is 411005047. The reversal of 411005041 is 140500114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 404854641 + 6150400 = 20121^2 + 2480^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-411005041 is a prime.
It is not a weakly prime, because it can be changed into another prime (411005047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205502520 + 205502521.
It is an arithmetic number, because the mean of its divisors is an integer number (205502521).
Almost surely, 2411005041 is an apocalyptic number.
It is an amenable number.
411005041 is a deficient number, since it is larger than the sum of its proper divisors (1).
411005041 is an equidigital number, since it uses as much as digits as its factorization.
411005041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 16.
The square root of 411005041 is about 20273.2592594284. The cubic root of 411005041 is about 743.5024138737.
Adding to 411005041 its reverse (140500114), we get a palindrome (551505155).
The spelling of 411005041 in words is "four hundred eleven million, five thousand, forty-one".
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