Base | Representation |
---|---|
bin | 100110010001110010… |
… | …001010100101010111 |
3 | 10221002100221101202111 |
4 | 212101302022211113 |
5 | 1133133220140120 |
6 | 30514211251451 |
7 | 2653336634530 |
oct | 462162124527 |
9 | 127070841674 |
10 | 41100552535 |
11 | 16481210499 |
12 | 7b705a9b87 |
13 | 3b50097893 |
14 | 1dbc811687 |
15 | 110842b75a |
hex | 991c8a957 |
41100552535 has 32 divisors (see below), whose sum is σ = 58842132480. Its totient is φ = 26946446208.
The previous prime is 41100552509. The next prime is 41100552539. The reversal of 41100552535 is 53525500114.
It is a cyclic number.
It is not a de Polignac number, because 41100552535 - 27 = 41100552407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41100552497 and 41100552506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41100552539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2158386 + ... + 2177344.
It is an arithmetic number, because the mean of its divisors is an integer number (1838816640).
Almost surely, 241100552535 is an apocalyptic number.
41100552535 is a deficient number, since it is larger than the sum of its proper divisors (17741579945).
41100552535 is a wasteful number, since it uses less digits than its factorization.
41100552535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21687.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 41100552535 in words is "forty-one billion, one hundred million, five hundred fifty-two thousand, five hundred thirty-five".
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