411011323 has 2 divisors, whose sum is σ = 411011324. Its totient is φ = 411011322.

The previous prime is 411011309. The next prime is 411011353. The reversal of 411011323 is 323110114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 411011323 - 2⁵ = 411011291 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 411011297 and 411011306.

It is not a weakly prime, because it can be changed into another prime (411011353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205505661 + 205505662.

It is an arithmetic number, because the mean of its divisors is an integer number (205505662).

Almost surely, 2^411011323 is an apocalyptic number.

411011323 is a deficient number, since it is larger than the sum of its proper divisors (1).

411011323 is an equidigital number, since it uses as much as digits as its factorization.

411011323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 411011323 is about 20273.4141919905. The cubic root of 411011323 is about 743.5062018713.

Adding to 411011323 its reverse (323110114), we get a palindrome (734121437).

It can be divided in two parts, 41101 and 1323, that added together give a palindrome (42424).

The spelling of 411011323 in words is "four hundred eleven million, eleven thousand, three hundred twenty-three".