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4110232443113 is a prime number
BaseRepresentation
bin111011110011111100111…
…100011101100011101001
3112112221020011111000022102
4323303330330131203221
51014320224001134423
612424114213503145
7602645251213226
oct73637474354351
915487204430272
104110232443113
11134515a073725
12564710641ab5
1323a7934cb934
14102d1734c94d
1571db36b9c28
hex3bcfcf1d8e9

4110232443113 has 2 divisors, whose sum is σ = 4110232443114. Its totient is φ = 4110232443112.

The previous prime is 4110232443091. The next prime is 4110232443127. The reversal of 4110232443113 is 3113442320114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3504953111104 + 605279332009 = 1872152^2 + 777997^2 .

It is a cyclic number.

It is not a de Polignac number, because 4110232443113 - 26 = 4110232443049 is a prime.

It is a super-2 number, since 2×41102324431132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4110232643113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055116221556 + 2055116221557.

It is an arithmetic number, because the mean of its divisors is an integer number (2055116221557).

Almost surely, 24110232443113 is an apocalyptic number.

It is an amenable number.

4110232443113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4110232443113 is an equidigital number, since it uses as much as digits as its factorization.

4110232443113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4110232443113 its reverse (3113442320114), we get a palindrome (7223674763227).

The spelling of 4110232443113 in words is "four trillion, one hundred ten billion, two hundred thirty-two million, four hundred forty-three thousand, one hundred thirteen".