Base | Representation |
---|---|
bin | 100110010001111001… |
… | …010000111001001111 |
3 | 10221002111102221101002 |
4 | 212101321100321033 |
5 | 1133134204212031 |
6 | 30514315210515 |
7 | 2653361515004 |
oct | 462171207117 |
9 | 127074387332 |
10 | 41102413391 |
11 | 16482271596 |
12 | 7b71146a3b |
13 | 3b50599890 |
14 | 1dbcb778ab |
15 | 1108697ccb |
hex | 991e50e4f |
41102413391 has 8 divisors (see below), whose sum is σ = 46867910544. Its totient is φ = 35708883840.
The previous prime is 41102413381. The next prime is 41102413421. The reversal of 41102413391 is 19331420114.
It is a happy number.
41102413391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 41102413391 - 210 = 41102412367 is a prime.
It is a super-2 number, since 2×411024133912 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41102413361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92991665 + ... + 92992106.
It is an arithmetic number, because the mean of its divisors is an integer number (5858488818).
Almost surely, 241102413391 is an apocalyptic number.
41102413391 is a deficient number, since it is larger than the sum of its proper divisors (5765497153).
41102413391 is a wasteful number, since it uses less digits than its factorization.
41102413391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 185983801.
The product of its (nonzero) digits is 2592, while the sum is 29.
The spelling of 41102413391 in words is "forty-one billion, one hundred two million, four hundred thirteen thousand, three hundred ninety-one".
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