Base | Representation |
---|---|
bin | 10010101100010000111100… |
… | …00111100100100110100101 |
3 | 12101112102220121011102210221 |
4 | 21112020132013210212211 |
5 | 20341414121113333013 |
6 | 223230340443244341 |
7 | 11441422066051345 |
oct | 1126103607444645 |
9 | 171472817142727 |
10 | 41103342324133 |
11 | 121079141a8711 |
12 | 473a12a2196b1 |
13 | 19c204a95370b |
14 | a215ab818d25 |
15 | 4b42d3d3108d |
hex | 25621e1e49a5 |
41103342324133 has 4 divisors (see below), whose sum is σ = 41103447358048. Its totient is φ = 41103237290220.
The previous prime is 41103342324019. The next prime is 41103342324181. The reversal of 41103342324133 is 33142324330114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 41103342324133 - 213 = 41103342315941 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41103042324133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51927753 + ... + 52713358.
It is an arithmetic number, because the mean of its divisors is an integer number (10275861839512).
Almost surely, 241103342324133 is an apocalyptic number.
It is an amenable number.
41103342324133 is a deficient number, since it is larger than the sum of its proper divisors (105033915).
41103342324133 is a wasteful number, since it uses less digits than its factorization.
41103342324133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105033914.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 41103342324133 its reverse (33142324330114), we get a palindrome (74245666654247).
The spelling of 41103342324133 in words is "forty-one trillion, one hundred three billion, three hundred forty-two million, three hundred twenty-four thousand, one hundred thirty-three".
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