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4111033321001 is a prime number
BaseRepresentation
bin111011110100101100101…
…011100100011000101001
3112120000021222110211020102
4323310230223210120221
51014323344012233001
612424325503235145
7603004144444205
oct73645453443051
915500258424212
104111033321001
111345530154082
125648b48a8ab5
1323a8903cb289
14102d91865b05
1571e0db66e6b
hex3bd2cae4629

4111033321001 has 2 divisors, whose sum is σ = 4111033321002. Its totient is φ = 4111033321000.

The previous prime is 4111033320983. The next prime is 4111033321063. The reversal of 4111033321001 is 1001233301114.

4111033321001 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3756526206976 + 354507114025 = 1938176^2 + 595405^2 .

It is a cyclic number.

It is not a de Polignac number, because 4111033321001 - 230 = 4109959579177 is a prime.

It is a super-2 number, since 2×41110333210012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4111033321201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055516660500 + 2055516660501.

It is an arithmetic number, because the mean of its divisors is an integer number (2055516660501).

Almost surely, 24111033321001 is an apocalyptic number.

It is an amenable number.

4111033321001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111033321001 is an equidigital number, since it uses as much as digits as its factorization.

4111033321001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 4111033321001 its reverse (1001233301114), we get a palindrome (5112266622115).

The spelling of 4111033321001 in words is "four trillion, one hundred eleven billion, thirty-three million, three hundred twenty-one thousand, one".