4111112013 has 4 divisors (see below), whose sum is σ = 5481482688. Its totient is φ = 2740741340.

The previous prime is 4111111997. The next prime is 4111112017. The reversal of 4111112013 is 3102111114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4111112013 - 2⁴ = 4111111997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4111111983 and 4111112001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4111112017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 685185333 + ... + 685185338.

It is an arithmetic number, because the mean of its divisors is an integer number (1370370672).

Almost surely, 2^4111112013 is an apocalyptic number.

It is an amenable number.

4111112013 is a deficient number, since it is larger than the sum of its proper divisors (1370370675).

4111112013 is a wasteful number, since it uses less digits than its factorization.

4111112013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1370370674.

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 4111112013 is about 64117.9539052830. The cubic root of 4111112013 is about 1601.9652950473.

Adding to 4111112013 its reverse (3102111114), we get a palindrome (7213223127).

The spelling of 4111112013 in words is "four billion, one hundred eleven million, one hundred twelve thousand, thirteen".