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411124433 is a prime number
BaseRepresentation
bin11000100000010…
…100001011010001
31001122121021200212
4120200110023101
51320221440213
6104443453505
713121333336
oct3040241321
91048537625
10411124433
111a1083965
12b5827295
1367237bc5
143c85c98d
152615e9a8
hex188142d1

411124433 has 2 divisors, whose sum is σ = 411124434. Its totient is φ = 411124432.

The previous prime is 411124423. The next prime is 411124457. The reversal of 411124433 is 334421114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 400320064 + 10804369 = 20008^2 + 3287^2 .

It is a cyclic number.

It is not a de Polignac number, because 411124433 - 216 = 411058897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 411124399 and 411124408.

It is not a weakly prime, because it can be changed into another prime (411124423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205562216 + 205562217.

It is an arithmetic number, because the mean of its divisors is an integer number (205562217).

Almost surely, 2411124433 is an apocalyptic number.

It is an amenable number.

411124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

411124433 is an equidigital number, since it uses as much as digits as its factorization.

411124433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1152, while the sum is 23.

The square root of 411124433 is about 20276.2036140891. The cubic root of 411124433 is about 743.5743997274.

Adding to 411124433 its reverse (334421114), we get a palindrome (745545547).

The spelling of 411124433 in words is "four hundred eleven million, one hundred twenty-four thousand, four hundred thirty-three".