Base | Representation |
---|---|
bin | 100110010010100001… |
… | …110000111010101001 |
3 | 10221010020102100001102 |
4 | 212102201300322221 |
5 | 1133144413432223 |
6 | 30515334531145 |
7 | 2653550664065 |
oct | 462241607251 |
9 | 127106370042 |
10 | 41113030313 |
11 | 16488263203 |
12 | 7b74806ab5 |
13 | 3b52846194 |
14 | 1dc033caa5 |
15 | 1109593928 |
hex | 992870ea9 |
41113030313 has 2 divisors, whose sum is σ = 41113030314. Its totient is φ = 41113030312.
The previous prime is 41113030291. The next prime is 41113030331. The reversal of 41113030313 is 31303031114.
Together with next prime (41113030331) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36279582784 + 4833447529 = 190472^2 + 69523^2 .
It is a cyclic number.
It is not a de Polignac number, because 41113030313 - 26 = 41113030249 is a prime.
It is not a weakly prime, because it can be changed into another prime (41113032313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556515156 + 20556515157.
It is an arithmetic number, because the mean of its divisors is an integer number (20556515157).
Almost surely, 241113030313 is an apocalyptic number.
It is an amenable number.
41113030313 is a deficient number, since it is larger than the sum of its proper divisors (1).
41113030313 is an equidigital number, since it uses as much as digits as its factorization.
41113030313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 41113030313 its reverse (31303031114), we get a palindrome (72416061427).
The spelling of 41113030313 in words is "forty-one billion, one hundred thirteen million, thirty thousand, three hundred thirteen".
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