Search a number
-
+
41113111001 = 49009838889
BaseRepresentation
bin100110010010100010…
…000100100111011001
310221010020120102201212
4212102202010213121
51133144424023001
630515340352505
72653551451244
oct462242044731
9127106512655
1041113111001
1116488308896
127b74845735
133b52873b21
141dc036025b
1511095ac7bb
hex9928849d9

41113111001 has 4 divisors (see below), whose sum is σ = 41113998900. Its totient is φ = 41112223104.

The previous prime is 41113110991. The next prime is 41113111019. The reversal of 41113111001 is 10011131114.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 274763776 + 40838347225 = 16576^2 + 202085^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41113111001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41113114001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 370436 + ... + 468453.

It is an arithmetic number, because the mean of its divisors is an integer number (10278499725).

Almost surely, 241113111001 is an apocalyptic number.

It is an amenable number.

41113111001 is a deficient number, since it is larger than the sum of its proper divisors (887899).

41113111001 is an equidigital number, since it uses as much as digits as its factorization.

41113111001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 887898.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 41113111001 its reverse (10011131114), we get a palindrome (51124242115).

The spelling of 41113111001 in words is "forty-one billion, one hundred thirteen million, one hundred eleven thousand, one".

Divisors: 1 49009 838889 41113111001