Base | Representation |
---|---|
bin | 100110010010100010… |
… | …000101010110010001 |
3 | 10221010020120120211222 |
4 | 212102202011112101 |
5 | 1133144424122001 |
6 | 30515340414425 |
7 | 2653551463061 |
oct | 462242052621 |
9 | 127106516758 |
10 | 41113114001 |
11 | 16488310073 |
12 | 7b74847415 |
13 | 3b528752bb |
14 | 1dc03613a1 |
15 | 11095ad61b |
hex | 992885591 |
41113114001 has 2 divisors, whose sum is σ = 41113114002. Its totient is φ = 41113114000.
The previous prime is 41113113983. The next prime is 41113114013. The reversal of 41113114001 is 10041131114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38704660225 + 2408453776 = 196735^2 + 49076^2 .
It is a cyclic number.
It is not a de Polignac number, because 41113114001 - 234 = 23933244817 is a prime.
It is not a weakly prime, because it can be changed into another prime (41113114201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556557000 + 20556557001.
It is an arithmetic number, because the mean of its divisors is an integer number (20556557001).
Almost surely, 241113114001 is an apocalyptic number.
It is an amenable number.
41113114001 is a deficient number, since it is larger than the sum of its proper divisors (1).
41113114001 is an equidigital number, since it uses as much as digits as its factorization.
41113114001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 41113114001 its reverse (10041131114), we get a palindrome (51154245115).
The spelling of 41113114001 in words is "forty-one billion, one hundred thirteen million, one hundred fourteen thousand, one".
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