41113140320 has 576 divisors, whose sum is σ = 124055318016. Its totient is φ = 12801761280.

The previous prime is 41113140317. The next prime is 41113140359. The reversal of 41113140320 is 2304131114.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 41113140292 and 41113140301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 495338999 + ... + 495339081.

It is an arithmetic number, because the mean of its divisors is an integer number (215373816).

Almost surely, 2^41113140320 is an apocalyptic number.

41113140320 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 41113140320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (62027659008).

41113140320 is an abundant number, since it is smaller than the sum of its proper divisors (82942177696).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41113140320 is a wasteful number, since it uses less digits than its factorization.

41113140320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 243 (or 228 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 41113140320 its reverse (2304131114), we get a palindrome (43417271434).

The spelling of 41113140320 in words is "forty-one billion, one hundred thirteen million, one hundred forty thousand, three hundred twenty".