Base | Representation |
---|---|
bin | 1011111101110010111… |
… | …01000100110101010011 |
3 | 1110022012120211121112011 |
4 | 11332321131010311103 |
5 | 23214000111100201 |
6 | 512512205243351 |
7 | 41463160250515 |
oct | 5767135046523 |
9 | 1408176747464 |
10 | 411133300051 |
11 | 1493a7036521 |
12 | 6781b863557 |
13 | 2ca01068556 |
14 | 15c82a51bb5 |
15 | aa64019151 |
hex | 5fb9744d53 |
411133300051 has 2 divisors, whose sum is σ = 411133300052. Its totient is φ = 411133300050.
The previous prime is 411133300043. The next prime is 411133300087. The reversal of 411133300051 is 150003331114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 411133300051 - 23 = 411133300043 is a prime.
It is a super-3 number, since 3×4111333000513 (a number of 36 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 411133299995 and 411133300031.
It is not a weakly prime, because it can be changed into another prime (411133300031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205566650025 + 205566650026.
It is an arithmetic number, because the mean of its divisors is an integer number (205566650026).
Almost surely, 2411133300051 is an apocalyptic number.
411133300051 is a deficient number, since it is larger than the sum of its proper divisors (1).
411133300051 is an equidigital number, since it uses as much as digits as its factorization.
411133300051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 411133300051 its reverse (150003331114), we get a palindrome (561136631165).
The spelling of 411133300051 in words is "four hundred eleven billion, one hundred thirty-three million, three hundred thousand, fifty-one".
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