Base | Representation |
---|---|
bin | 100110010010100011… |
… | …010011010011010101 |
3 | 10221010021011210211220 |
4 | 212102203103103111 |
5 | 1133200014331201 |
6 | 30515351320553 |
7 | 2653554263013 |
oct | 462243232325 |
9 | 127107153756 |
10 | 41113433301 |
11 | 16488508a56 |
12 | 7b74980159 |
13 | 3b52957735 |
14 | 1dc04058b3 |
15 | 1109623036 |
hex | 9928d34d5 |
41113433301 has 16 divisors (see below), whose sum is σ = 59611212864. Its totient is φ = 25099455744.
The previous prime is 41113433281. The next prime is 41113433303. The reversal of 41113433301 is 10333431114.
It is not a de Polignac number, because 41113433301 - 25 = 41113433269 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41113433303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10891975 + ... + 10895748.
It is an arithmetic number, because the mean of its divisors is an integer number (3725700804).
Almost surely, 241113433301 is an apocalyptic number.
It is an amenable number.
41113433301 is a deficient number, since it is larger than the sum of its proper divisors (18497779563).
41113433301 is a wasteful number, since it uses less digits than its factorization.
41113433301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21787780.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 41113433301 its reverse (10333431114), we get a palindrome (51446864415).
The spelling of 41113433301 in words is "forty-one billion, one hundred thirteen million, four hundred thirty-three thousand, three hundred one".
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