Base | Representation |
---|---|
bin | 10010101100100101001100… |
… | …00101001000100110101011 |
3 | 12101120110222012212022012101 |
4 | 21112102212011020212223 |
5 | 20342103402102234011 |
6 | 223235335302354231 |
7 | 11442255351025216 |
oct | 1126224605104653 |
9 | 171513865768171 |
10 | 41114213321131 |
11 | 12111492635655 |
12 | 4740262a2b977 |
13 | 19c3090c21312 |
14 | a21d1d50877d |
15 | 4b471d3dc2c1 |
hex | 2564a61489ab |
41114213321131 has 2 divisors, whose sum is σ = 41114213321132. Its totient is φ = 41114213321130.
The previous prime is 41114213321123. The next prime is 41114213321161. The reversal of 41114213321131 is 13112331241114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41114213321131 - 23 = 41114213321123 is a prime.
It is a super-2 number, since 2×411142133211312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 41114213321131.
It is not a weakly prime, because it can be changed into another prime (41114213321161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20557106660565 + 20557106660566.
It is an arithmetic number, because the mean of its divisors is an integer number (20557106660566).
Almost surely, 241114213321131 is an apocalyptic number.
41114213321131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41114213321131 is an equidigital number, since it uses as much as digits as its factorization.
41114213321131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 28.
Adding to 41114213321131 its reverse (13112331241114), we get a palindrome (54226544562245).
The spelling of 41114213321131 in words is "forty-one trillion, one hundred fourteen billion, two hundred thirteen million, three hundred twenty-one thousand, one hundred thirty-one".
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