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411152225963 is a prime number
BaseRepresentation
bin1011111101110101001…
…01010001011010101011
31110022020220110010222212
411332322211101122223
523214014432212323
6512514123035335
741463510154223
oct5767245213253
91408226403885
10411152225963
11149406792876
126782606bb4b
132ca04c63b0b
1415c8537b083
15aa65a06b78
hex5fba9516ab

411152225963 has 2 divisors, whose sum is σ = 411152225964. Its totient is φ = 411152225962.

The previous prime is 411152225933. The next prime is 411152225971. The reversal of 411152225963 is 369522251114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411152225963 is a prime.

It is a super-2 number, since 2×4111522259632 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 411152225963.

It is not a weakly prime, because it can be changed into another prime (411152225933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205576112981 + 205576112982.

It is an arithmetic number, because the mean of its divisors is an integer number (205576112982).

Almost surely, 2411152225963 is an apocalyptic number.

411152225963 is a deficient number, since it is larger than the sum of its proper divisors (1).

411152225963 is an equidigital number, since it uses as much as digits as its factorization.

411152225963 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 41.

The spelling of 411152225963 in words is "four hundred eleven billion, one hundred fifty-two million, two hundred twenty-five thousand, nine hundred sixty-three".