Base | Representation |
---|---|
bin | 111011110101100110011… |
… | …010111101000111110001 |
3 | 112120002210111022001220212 |
4 | 323311212122331013301 |
5 | 1014332340010410101 |
6 | 12425005550313505 |
7 | 603040146451526 |
oct | 73654632750761 |
9 | 15502714261825 |
10 | 4112002044401 |
11 | 1345987a55329 |
12 | 564b251b8895 |
13 | 23a9b60073a4 |
14 | 10304439114d |
15 | 71e68c1b1bb |
hex | 3bd666bd1f1 |
4112002044401 has 2 divisors, whose sum is σ = 4112002044402. Its totient is φ = 4112002044400.
The previous prime is 4112002044379. The next prime is 4112002044413. The reversal of 4112002044401 is 1044402002114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3325899927025 + 786102117376 = 1823705^2 + 886624^2 .
It is a cyclic number.
It is not a de Polignac number, because 4112002044401 - 218 = 4112001782257 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (4112002044461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056001022200 + 2056001022201.
It is an arithmetic number, because the mean of its divisors is an integer number (2056001022201).
Almost surely, 24112002044401 is an apocalyptic number.
It is an amenable number.
4112002044401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4112002044401 is an equidigital number, since it uses as much as digits as its factorization.
4112002044401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1024, while the sum is 23.
Adding to 4112002044401 its reverse (1044402002114), we get a palindrome (5156404046515).
The spelling of 4112002044401 in words is "four trillion, one hundred twelve billion, two million, forty-four thousand, four hundred one".
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