Base | Representation |
---|---|
bin | 111011110101101100011… |
… | …001000100001010001010 |
3 | 112120010001110210010100121 |
4 | 323311230121010022022 |
5 | 1014333041131242414 |
6 | 12425023525253454 |
7 | 603042504043162 |
oct | 73655431041212 |
9 | 15503043703317 |
10 | 4112102212234 |
11 | 1345a29550965 |
12 | 564b5286428a |
13 | 23aa009a93b3 |
14 | 1030537c75a2 |
15 | 71e72905724 |
hex | 3bd6c64428a |
4112102212234 has 4 divisors (see below), whose sum is σ = 6168153318354. Its totient is φ = 2056051106116.
The previous prime is 4112102212121. The next prime is 4112102212271. The reversal of 4112102212234 is 4322122012114.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 3738604001209 + 373498211025 = 1933547^2 + 611145^2 .
It is a junction number, because it is equal to n+sod(n) for n = 4112102212199 and 4112102212208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1028025553057 + ... + 1028025553060.
Almost surely, 24112102212234 is an apocalyptic number.
4112102212234 is a deficient number, since it is larger than the sum of its proper divisors (2056051106120).
4112102212234 is a wasteful number, since it uses less digits than its factorization.
4112102212234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2056051106119.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4112102212234 its reverse (4322122012114), we get a palindrome (8434224224348).
The spelling of 4112102212234 in words is "four trillion, one hundred twelve billion, one hundred two million, two hundred twelve thousand, two hundred thirty-four".
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