Base | Representation |
---|---|
bin | 100110010011000001… |
… | …010100011010000011 |
3 | 10221010210222120212122 |
4 | 212103001110122003 |
5 | 1133204023132042 |
6 | 30520232114455 |
7 | 2654011205162 |
oct | 462301243203 |
9 | 127123876778 |
10 | 41121302147 |
11 | 164919a2a32 |
12 | 7b77535a2b |
13 | 3b54481263 |
14 | 1dc14933d9 |
15 | 110a1797d2 |
hex | 993054683 |
41121302147 has 2 divisors, whose sum is σ = 41121302148. Its totient is φ = 41121302146.
The previous prime is 41121302041. The next prime is 41121302153. The reversal of 41121302147 is 74120312114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41121302147 - 28 = 41121301891 is a prime.
It is a super-2 number, since 2×411213021472 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41121302647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20560651073 + 20560651074.
It is an arithmetic number, because the mean of its divisors is an integer number (20560651074).
Almost surely, 241121302147 is an apocalyptic number.
41121302147 is a deficient number, since it is larger than the sum of its proper divisors (1).
41121302147 is an equidigital number, since it uses as much as digits as its factorization.
41121302147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
The spelling of 41121302147 in words is "forty-one billion, one hundred twenty-one million, three hundred two thousand, one hundred forty-seven".
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