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4112220433 is a prime number
BaseRepresentation
bin1111010100011011…
…1000000100010001
3101121120212102221111
43311012320010101
531410212023213
61520015053321
7203622203566
oct36506700421
911546772844
104112220433
111820272092
12969211241
13506c53639
142b020686d
15191040a3d
hexf51b8111

4112220433 has 2 divisors, whose sum is σ = 4112220434. Its totient is φ = 4112220432.

The previous prime is 4112220379. The next prime is 4112220449. The reversal of 4112220433 is 3340222114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4061767824 + 50452609 = 63732^2 + 7103^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4112220433 is a prime.

It is not a weakly prime, because it can be changed into another prime (4112220473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056110216 + 2056110217.

It is an arithmetic number, because the mean of its divisors is an integer number (2056110217).

Almost surely, 24112220433 is an apocalyptic number.

It is an amenable number.

4112220433 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112220433 is an equidigital number, since it uses as much as digits as its factorization.

4112220433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 22.

The square root of 4112220433 is about 64126.5969235855. The cubic root of 4112220433 is about 1602.1092537304.

Adding to 4112220433 its reverse (3340222114), we get a palindrome (7452442547).

The spelling of 4112220433 in words is "four billion, one hundred twelve million, two hundred twenty thousand, four hundred thirty-three".